5u^2-29u+20=0

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Solution for 5u^2-29u+20=0 equation:


Simplifying
5u2 + -29u + 20 = 0

Reorder the terms:
20 + -29u + 5u2 = 0

Solving
20 + -29u + 5u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(4 + -5u)(5 + -1u) = 0

Subproblem 1

Set the factor '(4 + -5u)' equal to zero and attempt to solve: Simplifying 4 + -5u = 0 Solving 4 + -5u = 0 Move all terms containing u to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5u = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5u = 0 + -4 -5u = 0 + -4 Combine like terms: 0 + -4 = -4 -5u = -4 Divide each side by '-5'. u = 0.8 Simplifying u = 0.8

Subproblem 2

Set the factor '(5 + -1u)' equal to zero and attempt to solve: Simplifying 5 + -1u = 0 Solving 5 + -1u = 0 Move all terms containing u to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1u = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1u = 0 + -5 -1u = 0 + -5 Combine like terms: 0 + -5 = -5 -1u = -5 Divide each side by '-1'. u = 5 Simplifying u = 5

Solution

u = {0.8, 5}

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